11x^2+16=192

Solution for 11x^2+16=192 equation:

11x^2+16=192

We move all terms to the left:

11x^2+16-(192)=0

We add all the numbers together, and all the variables

11x^2-176=0

a = 11; b = 0; c = -176;
Δ = b2-4ac
Δ = 02-4·11·(-176)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-88}{2*11}=\frac{-88}{22}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+88}{2*11}=\frac{88}{22}
=4
$